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Biology - Cell Biology and Biochemistry

Cell Structure

Cell Theory

  1. All living organisms are composed of one or more cells
  2. The cell is the basic unit of structure and function in all living organisms
  3. All cells arise from pre-existing cells

Prokaryotic vs Eukaryotic Cells

FeatureProkaryotic CellsEukaryotic Cells
NucleusNo true nucleus (nucleoid region)True nucleus with nuclear envelope
Membrane-bound organellesAbsentPresent
DNACircular, nakedLinear, associated with histones
Ribosomes70S (smaller)80S (larger)
Cell size1-5 micrometres10-100 micrometres
Cell wallPresent (peptidoglycan in bacteria)Present in plants (cellulose), absent in animals
ExamplesBacteria, ArchaeaAnimals, Plants, Fungi, Protists

Plant vs Animal Cells

FeaturePlant CellsAnimal Cells
Cell wallPresent (cellulose)Absent
ChloroplastsPresentAbsent
Large central vacuolePresentSmall, temporary vacuoles
CentriolesAbsentPresent
PlasmodesmataPresentAbsent
ShapeFixed (rectangular)Variable (irregular)
Stored carbohydrateStarchGlycogen

Cell Organelles

Nucleus

The nucleus is the control centre of the cell. It contains:

  • Nuclear envelope: Double membrane with nuclear pores that control the movement of substances in and out
  • Nucleolus: Dark-staining region where ribosomal RNA (rRNA) is synthesised
  • Chromatin: DNA wrapped around histone proteins; condenses into chromosomes during cell division

Functions:

  • Controls cell activities through gene expression
  • Stores genetic information (DNA)
  • Site of DNA replication and transcription

Mitochondria

Mitochondria are the sites of aerobic respiration, producing ATP through the Krebs cycle and oxidative phosphorylation.

Structure:

  • Outer membrane: Permeable to small molecules
  • Inner membrane: Folded into cristae to increase surface area; site of the electron transport chain
  • Matrix: Contains enzymes for the Krebs cycle, mitochondrial DNA, and ribosomes

C6H12O6+6O26CO2+6H2O+ATP\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 + 6\mathrm{O}_2 \to 6\mathrm{CO}_2 + 6\mathrm{H}_2\mathrm{O} + \mathrm{ATP}

Endoplasmic Reticulum (ER)

Rough ER (RER):

  • Studded with ribosomes
  • Involved in protein synthesis and transport
  • Proteins enter the ER lumen for folding and modification

Smooth ER (SER):

  • No ribosomes
  • Involved in lipid synthesis, detoxification, and calcium storage

Golgi Apparatus

A stack of flattened membrane-bound sacs (cisternae) that modifies, sorts, and packages proteins and lipids.

Functions:

  • Modifies proteins (e.g., adding carbohydrate groups to form glycoproteins)
  • Packages proteins into vesicles for transport
  • Forms lysosomes (in animal cells)

Ribosomes

Ribosomes are the sites of protein synthesis (translation).

  • Free ribosomes: Float in the cytoplasm; synthesise proteins for use within the cell
  • Bound ribosomes: Attached to the RER; synthesise proteins for secretion or for the cell membrane

Lysosomes

Membrane-bound vesicles containing digestive enzymes (hydrolytic enzymes). Functions include:

  • Breaking down worn-out organelles (autophagy)
  • Digesting material engulfed by phagocytosis
  • Releasing enzymes outside the cell (extracellular digestion)

Chloroplasts (Plant Cells Only)

The site of photosynthesis.

Structure:

  • Double membrane: Outer and inner membrane
  • Thylakoids: Flattened sacs containing chlorophyll; site of the light-dependent reactions
  • Grana: Stacks of thylakoids
  • Stroma: Fluid-filled space; site of the light-independent reactions (Calvin cycle)

6CO2+6H2OlightC6H12O6+6O26\mathrm{CO}_2 + 6\mathrm{H}_2\mathrm{O} \xrightarrow{\mathrm{light}} \mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6 + 6\mathrm{O}_2

Cell Membrane

The cell membrane (plasma membrane) is a phospholipid bilayer with embedded proteins.

Fluid Mosaic Model:

  • Fluid: Individual phospholipid molecules can move laterally within the layer
  • Mosaic: Various proteins are embedded in the bilayer, creating a pattern

Components:

  • Phospholipids: form the basic bilayer structure
  • Intrinsic (integral) proteins: span the entire membrane; involved in transport and signalling
  • Extrinsic (peripheral) proteins: attached to the surface; involved in cell recognition and enzymatic activity
  • Cholesterol: regulates membrane fluidity
  • Glycolipids and glycoproteins: involved in cell recognition
info

The cell membrane is selectively permeable: it allows some substances to pass through freely but restricts others. Small, non-polar molecules (e.g., O2\mathrm{O}_2, CO2\mathrm{CO}_2) diffuse through easily, while large or charged molecules require transport proteins.


Membrane Transport

Passive Transport (No Energy Required)

Simple Diffusion

Movement of molecules from a region of higher concentration to a region of lower concentration, directly through the phospholipid bilayer.

  • Only for small, non-polar molecules (e.g., O2\mathrm{O}_2, CO2\mathrm{CO}_2, lipid-soluble substances)
  • Net movement stops at equilibrium (dynamic equilibrium)
  • Rate depends on: concentration gradient, temperature, surface area, distance

Facilitated Diffusion

Movement of molecules down their concentration gradient through transport proteins.

  • Channel proteins: Form hydrophilic pores for specific ions (e.g., Na+\mathrm{Na}^+, K+\mathrm{K}^+, Ca2+\mathrm{Ca}^{2+})
  • Carrier proteins: Bind to specific molecules, undergo conformational change, and release on the other side
  • Used for larger or polar molecules (e.g., glucose, amino acids, ions)

Osmosis

The movement of water molecules from a region of higher water potential to a region of lower water potential, through a selectively permeable membrane.

Water potential (Ψ\Psi) is measured in kilopascals (kPa). Pure water has Ψ=0kPa\Psi = 0 \mathrm{ kPa}. Adding solutes decreases water potential (makes it more negative).

Osmosis in animal cells:

SolutionWater PotentialEffect on Cell
HypotonicHigher than cellCell swells and may burst (lysis)
IsotonicEqual to cellNo net movement
HypertonicLower than cellCell shrinks (crenation)

Osmosis in plant cells:

SolutionEffect on Cell
HypotonicCell becomes turgid (firm); useful for plant support
IsotonicNo net movement
HypertonicCytoplasm and vacuole shrink; cell becomes plasmolysed

Active Transport (Energy Required)

Movement of molecules against their concentration gradient (from low to high concentration), requiring ATP and carrier proteins.

  • Specific to certain molecules (e.g., Na+/K+\mathrm{Na}^+/\mathrm{K}^+ pump, absorption of minerals by root hair cells)
  • Can become saturated at high concentrations (carrier proteins are limiting)
  • Inhibited by metabolic poisons (e.g., cyanide) that block ATP production

Bulk Transport

Endocytosis

The cell membrane engulfs material to bring it into the cell.

  • Phagocytosis: "Cell eating" — engulfing solid particles (e.g., white blood cells engulfing bacteria)
  • Pinocytosis: "Cell drinking" — engulfing liquid droplets

Exocytosis

Vesicles fuse with the cell membrane to release contents outside the cell (e.g., secretion of hormones, neurotransmitters).


Biological Molecules

Carbohydrates

General formula: Cx(H2O)y\mathrm{C}_x(\mathrm{H}_2\mathrm{O})_y

Monosaccharides:

  • Glucose (C6H12O6\mathrm{C}_6\mathrm{H}_{12}\mathrm{O}_6): primary energy source
  • Fructose: found in fruits
  • Galactose: component of milk sugar
  • Ribose and deoxyribose: in RNA and DNA respectively

Disaccharides (formed by condensation, broken by hydrolysis):

DisaccharideComponent Monosaccharides
MaltoseGlucose + Glucose
SucroseGlucose + Fructose
LactoseGlucose + Galactose

Polysaccharides:

  • Starch: Energy storage in plants (amylose: helical; amylopectin: branched)
  • Glycogen: Energy storage in animals (highly branched)
  • Cellulose: Structural in plants (beta-glucose, straight chains, hydrogen bonds)
  • Chitin: Structural in arthropod exoskeletons and fungal cell walls

Tests for carbohydrates:

  • Benedict's test: Reducing sugars (e.g., glucose) produce a brick-red precipitate when heated with Benedict's reagent
  • Iodine test: Starch turns blue-black

Proteins

Proteins are polymers of amino acids.

Amino acid structure:

Each amino acid has an amino group (NH2\mathrm{NH}_2), a carboxyl group (COOH\mathrm{COOH}), a hydrogen atom, and an R group (side chain), all bonded to a central carbon atom.

Peptide bond formation:

Amino acids join by condensation reactions, forming peptide bonds (CONH\mathrm{-CO-NH-}) and releasing water.

  • Dipeptide: 2 amino acids
  • Polypeptide: many amino acids

Protein structure levels:

LevelDescriptionBonds
PrimarySequence of amino acidsPeptide bonds
SecondaryAlpha-helix or beta-pleated sheetHydrogen bonds
Tertiary3D folding of the polypeptideH-bonds, ionic bonds, disulphide bridges, hydrophobic interactions
QuaternaryMultiple polypeptide chainsSame as tertiary + more

Tests for proteins:

  • Biuret test: Add Biuret reagent (NaOH + CuSO4_4); violet/purple colour indicates protein

Lipids

Lipids are organic molecules that are insoluble in water but soluble in organic solvents.

Triglycerides:

  • Formed from one glycerol + three fatty acids
  • Joined by ester bonds (condensation reaction)
  • Energy storage molecules
  • Contain more energy per gram than carbohydrates

Phospholipids:

  • Similar to triglycerides but one fatty acid is replaced by a phosphate group
  • Amphipathic: hydrophilic head (phosphate) and hydrophobic tail (fatty acids)
  • Form the cell membrane bilayer

Saturated vs unsaturated fatty acids:

  • Saturated: no double bonds (C-C), solid at room temperature (animal fats)
  • Unsaturated: one or more double bonds (C=C), liquid at room temperature (plant oils)

Test for lipids:

  • Ethanol emulsion test: Dissolve in ethanol, pour into water; cloudy white emulsion indicates lipids

Nucleic Acids

DNA (Deoxyribonucleic Acid):

  • Double-stranded helix
  • Sugar: deoxyribose
  • Bases: adenine (A), thymine (T), guanine (G), cytosine (C)
  • Base pairing: A-T (2 H-bonds), G-C (3 H-bonds)
  • Stores genetic information

RNA (Ribonucleic Acid):

  • Usually single-stranded
  • Sugar: ribose
  • Bases: A, U (uracil replaces thymine), G, C
  • Types: mRNA (messenger), tRNA (transfer), rRNA (ribosomal)

Enzymes

Definition

Enzymes are biological catalysts produced by living cells. They are globular proteins that speed up biochemical reactions without being consumed.

Properties of Enzymes

  • Specific: each enzyme catalyses one particular reaction (or a small group of reactions)
  • Not used up: can be reused many times
  • Work in small amounts
  • Affected by temperature and pH
  • Protein in nature: denatured by extreme conditions

Lock and Key Hypothesis

The substrate (reactant) fits into the active site of the enzyme like a key fits into a lock. The active site has a specific complementary shape to the substrate.

Induced Fit Hypothesis

A more refined model: the active site changes shape slightly when the substrate binds, improving the fit. This lowers the activation energy of the reaction.

Factors Affecting Enzyme Activity

Temperature:

  • Rate increases with temperature (up to the optimum)
  • Beyond the optimum, the enzyme denatures (active site changes shape irreversibly)
  • Human enzymes: optimum around 37C37^\circ\mathrm{C}

pH:

  • Each enzyme has an optimum pH
  • Extreme pH causes denaturation by disrupting ionic and hydrogen bonds
  • Pepsin: optimum pH 2 (stomach)
  • Trypsin: optimum pH 8 (small intestine)

Substrate concentration:

  • Increasing substrate concentration increases the rate (up to a point)
  • At saturation, all active sites are occupied; rate plateaus (Vmax)

Enzyme concentration:

  • Increasing enzyme concentration increases the rate (provided substrate is not limiting)
warning

Denaturation is irreversible. Once an enzyme is denatured by heat or extreme pH, it cannot regain its function. This is different from a temporary decrease in activity at sub-optimal conditions.

Worked Example 1

An enzyme has an optimum temperature of 40C40^\circ\mathrm{C}. At 20C20^\circ\mathrm{C}, the reaction rate is 0.30.3 units/s. At 40C40^\circ\mathrm{C}, the rate is 1.21.2 units/s. Calculate the Q10 (temperature coefficient).

Q10=Rateat(T+10)RateatTQ_{10} = \frac{\mathrm{Rate at }(T + 10)}{\mathrm{Rate at } T}

Between 20C20^\circ\mathrm{C} and 30C30^\circ\mathrm{C}: Q10Q_{10} might be approximately 2 (typical for biological reactions). Without the 30C30^\circ\mathrm{C} data, we can estimate the overall effect:

From 20C20^\circ\mathrm{C} to 40C40^\circ\mathrm{C} (a 20C20^\circ\mathrm{C} increase):

Rateincreasefactor=1.20.3=4\mathrm{Rate increase factor} = \frac{1.2}{0.3} = 4

This is consistent with Q102Q_{10} \approx 2 (since 22=42^2 = 4).

Enzyme Inhibition

Competitive inhibition:

  • Inhibitor has a similar shape to the substrate
  • Competes with the substrate for the active site
  • Can be overcome by increasing substrate concentration
  • Example: malonate inhibiting succinate dehydrogenase

Non-competitive inhibition:

  • Inhibitor binds to a site other than the active site (allosteric site)
  • Changes the shape of the active site
  • Cannot be overcome by increasing substrate concentration
  • Example: heavy metal ions (lead, mercury)

Cellular Respiration

Glycolysis (Cytoplasm)

  1. Glucose (6C) is phosphorylated (uses 2 ATP)
  2. Glucose is split into two molecules of triose phosphate (3C)
  3. Triose phosphate is oxidised and dehydrogenated (produces 2 NADH)
  4. Net production: 2 ATP, 2 NADH, 2 pyruvate (3C)
  • Pyruvate (3C) is decarboxylated and dehydrogenated
  • Forms acetyl CoA (2C) + CO2\mathrm{CO}_2 + NADH

Krebs Cycle (Mitochondrial Matrix)

For each glucose molecule (two turns of the cycle):

  • 2 CO2\mathrm{CO}_2 released
  • 3 NADH produced per turn (6 total)
  • 1 FADH2_2 produced per turn (2 total)
  • 1 ATP produced per turn (2 total)
  • Regenerates oxaloacetate (4C)

Oxidative Phosphorylation (Inner Mitochondrial Membrane)

  • NADH and FADH2_2 donate electrons to the electron transport chain
  • Energy released pumps protons across the inner membrane
  • Protons flow back through ATP synthase, producing ATP
  • Oxygen is the final electron acceptor, forming water

ATP Yield per Glucose

StageATP (net)
Glycolysis2
Krebs cycle2
Oxidative phosphorylation (from NADH)28
Oxidative phosphorylation (from FADH2_2)4
Totalapproximately 36-38
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The actual ATP yield may be less than 38 due to the cost of transporting NADH from glycolysis into the mitochondria. Many textbooks now quote approximately 30-32 ATP per glucose.


Photosynthesis

Light-Dependent Reactions (Thylakoid Membrane)

  1. Light energy is absorbed by chlorophyll in Photosystem II
  2. Water is split (photolysis): H2O2H++2e+12O2\mathrm{H}_2\mathrm{O} \to 2\mathrm{H}^+ + 2e^- + \frac{1}{2}\mathrm{O}_2
  3. Electrons pass through the electron transport chain, generating ATP
  4. Light is absorbed by Photosystem I; electrons are re-energised
  5. Electrons reduce NADP+^+ to NADPH

Products: ATP, NADPH, O2\mathrm{O}_2

Light-Independent Reactions / Calvin Cycle (Stroma)

  1. CO2\mathrm{CO}_2 is fixed by ribulose bisphosphate (RuBP, 5C) using the enzyme RuBisCO
  2. Forms an unstable 6C compound that splits into two molecules of glycerate-3-phosphate (GP, 3C)
  3. GP is reduced to triose phosphate (TP, 3C) using ATP and NADPH
  4. Some TP is used to make glucose and other organic compounds
  5. Most TP is used to regenerate RuBP (uses ATP)

For every 3 CO2\mathrm{CO}_2 molecules fixed: 1 molecule of triose phosphate (3C) is produced. It takes 6 CO2\mathrm{CO}_2 molecules to produce 1 molecule of glucose (6C).

Limiting Factors in Photosynthesis

FactorEffect
Light intensityIncreases rate up to a plateau (light saturation point)
CO2\mathrm{CO}_2 concentrationIncreases rate up to a plateau
TemperatureIncreases rate up to optimum, then decreases (enzyme denaturation)

Summary Table

TopicKey ConceptLocation
Prokaryote vs EukaryoteNucleus, organelles, ribosome sizeAll cells
Membrane transportDiffusion, osmosis, active transportCell membrane
CarbohydratesMonosaccharides, disaccharides, polysaccharidesAll organisms
ProteinsAmino acids, peptide bonds, 4 levels of structureAll organisms
EnzymesLock and key, induced fit, denaturationAll organisms
RespirationGlycolysis, Krebs, oxidative phosphorylationMitochondria
PhotosynthesisLight-dependent, Calvin cycleChloroplasts

Exam Tips

  • Always distinguish between prokaryotic and eukaryotic cells in comparison questions.
  • For membrane transport, clearly state whether energy is required and the direction of movement relative to the concentration gradient.
  • In enzyme questions, always mention the effect on the active site when discussing denaturation.
  • For photosynthesis limiting factor graphs, identify which factor is limiting at each point on the curve.
  • When describing biochemical pathways (respiration, photosynthesis), name the specific location of each stage.

Worked Example: Cell Membrane Structure

Explain how the fluid mosaic model of the cell membrane accounts for the following properties: (a) selective permeability, (b) ability of cells to communicate, (c) flexibility for phagocytosis.

If you get this wrong, revise: Cell Organelles -- Cell Membrane

Solution

(a) Selective permeability: The phospholipid bilayer allows small, non-polar molecules (O2_2, CO2_2) to diffuse through freely, while blocking large or charged molecules. Channel and carrier proteins provide selective pathways for specific ions and polar molecules (e.g., glucose via carrier proteins, Na+^+ via channel proteins). Cholesterol modulates fluidity, maintaining permeability at different temperatures.

(b) Cell communication: Glycoproteins and glycolipids on the cell surface act as recognition markers (e.g., MHC proteins for immune recognition, hormone receptors). Extrinsic proteins on the outer surface can bind signalling molecules, triggering intracellular responses via signal transduction.

(c) Flexibility: The phospholipid molecules can move laterally within the bilayer (fluid nature), allowing the membrane to bend and change shape. This enables vesicle formation during endocytosis (phagocytosis) and exocytosis, and allows cells to change shape (e.g., red blood cells squeezing through capillaries).

Exam-Style Practice Questions

Question 1: Describe the structure of the cell membrane and explain how its structure relates to its function.

The cell membrane is a phospholipid bilayer with embedded proteins (fluid mosaic model). The hydrophobic tails face inward and hydrophilic heads face outward, making the membrane a barrier to water-soluble substances. Channel and carrier proteins allow selective transport. Cholesterol maintains fluidity. Glycoproteins on the surface enable cell recognition. The fluid nature allows vesicle formation (endocytosis/exocytosis).

Question 2: Explain the effect of increasing temperature on enzyme activity from 0C0^\circ\mathrm{C} to 60C60^\circ\mathrm{C}.

From 0C0^\circ\mathrm{C} to the optimum (approximately 3740C37-40^\circ\mathrm{C}): increasing temperature increases kinetic energy, leading to more frequent collisions between enzyme and substrate molecules, increasing the rate of reaction. Beyond the optimum temperature, the increased kinetic energy breaks the bonds maintaining the tertiary structure of the enzyme, causing the active site to change shape (denaturation). The substrate can no longer fit, and the reaction rate decreases sharply.

Question 3: Compare and contrast aerobic and anaerobic respiration.

Similarities: Both begin with glycolysis; both produce ATP.

Differences: Aerobic respiration requires oxygen and occurs in the mitochondria, producing approximately 36-38 ATP per glucose with CO2\mathrm{CO}_2 and H2O\mathrm{H}_2\mathrm{O} as by-products. Anaerobic respiration occurs without oxygen, only in the cytoplasm, producing 2 ATP per glucose. In animals, it produces lactate; in yeast, it produces ethanol and CO2\mathrm{CO}_2.


Cell Division

Mitosis

Mitosis is the process of cell division that produces two genetically identical daughter cells, each with the same number of chromosomes as the parent cell.

Functions of mitosis:

  • Growth: increasing the number of cells in an organism
  • Repair: replacing damaged or dead cells
  • Asexual reproduction: in some organisms

Stages of Mitosis

StageKey Events
ProphaseChromatin condenses into chromosomes; nucleolus disappears; centrioles move to poles; spindle fibres form; nuclear membrane begins to break down
MetaphaseChromosomes line up at the equator (metaphase plate); spindle fibres attach to centromeres
AnaphaseSister chromatids separate at the centromere; spindle fibres pull chromatids to opposite poles; chromosomes have a V-shape
TelophaseChromosomes arrive at poles and decondense; nuclear membrane reforms; nucleolus reappears; spindle fibres break down
CytokinesisCytoplasm divides; in animal cells, a cleavage furrow forms; in plant cells, a cell plate forms

Worked Example 2 (Cell Division)

A cell in the G2 phase of the cell cycle has 46 chromosomes. How many chromosomes and chromatids will be present in each daughter cell after mitosis?

After mitosis: each daughter cell has 46 chromosomes (each consisting of one chromatid).

During S phase (before mitosis), each chromosome replicates to form two sister chromatids. So at the start of mitosis, there are 46 chromosomes (92 chromatids). After anaphase, the chromatids separate, and each daughter cell receives 46 single-chromatid chromosomes.

Meiosis

Meiosis is a type of cell division that produces four genetically different daughter cells, each with half the number of chromosomes of the parent cell. It is essential for sexual reproduction.

Key differences from mitosis:

FeatureMitosisMeiosis
Number of divisionsOneTwo
Number of daughter cellsTwoFour
Chromosome numberSame as parent (diploid)Half of parent (haploid)
Genetic variationIdentical daughter cellsDifferent daughter cells
FunctionGrowth, repair, asexual reproductionProduction of gametes (sex cells)

Sources of genetic variation in meiosis:

  1. Crossing over: During prophase I, homologous chromosomes exchange segments of DNA. This creates new combinations of alleles on the same chromosome.
  2. Independent assortment: During metaphase I, homologous pairs line up randomly at the equator. Different combinations of maternal and paternal chromosomes are distributed to daughter cells.
  3. Random fertilisation: Any sperm can fertilise any egg, further increasing genetic diversity.

Meiosis Stages

Meiosis I (reductional division):

  • Prophase I: Homologous chromosomes pair up (synapsis); crossing over occurs
  • Metaphase I: Homologous pairs line up at the equator
  • Anaphase I: Homologous chromosomes separate (sister chromatids remain together)
  • Telophase I: Two cells form, each with half the chromosome number (but each chromosome still has two chromatids)

Meiosis II (equational division):

  • Prophase II: Chromosomes condense again
  • Metaphase II: Chromosomes line up singly at the equator
  • Anaphase II: Sister chromatids separate
  • Telophase II: Four haploid daughter cells form

The Cell Cycle

The cell cycle describes the sequence of events from one cell division to the next.

PhaseDescriptionDuration (typical)
G1 (Gap 1)Cell growth, normal metabolism, organelle duplicationVariable
S (Synthesis)DNA replication6-8 hours
G2 (Gap 2)Preparation for mitosis, protein synthesis2-4 hours
M (Mitosis)Cell division1-2 hours
CytokinesisCytoplasmic divisionOverlaps with M phase

G1, S, and G2 together are called interphase, which accounts for approximately 90% of the cell cycle.

Control of the Cell Cycle

The cell cycle is controlled by checkpoints:

  • G1 checkpoint: Checks if the cell is large enough and DNA is undamaged before entering S phase
  • G2 checkpoint: Checks if DNA has been replicated correctly before entering M phase
  • Spindle checkpoint (M checkpoint): Checks if all chromosomes are properly attached to spindle fibres before anaphase

Cancer and Uncontrolled Cell Division

Cancer is a disease caused by uncontrolled cell division, resulting in the formation of tumours.

  • Benign tumours: Grow slowly, remain localised, do not spread
  • Malignant tumours: Grow rapidly, invade surrounding tissues, can spread to other parts of the body (metastasis)

Causes of cancer:

  • Mutations in proto-oncogenes (become oncogenes, promoting cell division)
  • Mutations in tumour suppressor genes (losing their inhibitory function)
  • Exposure to carcinogens: UV radiation, tobacco smoke, certain chemicals, ionising radiation
  • Some viruses (e.g., HPV, hepatitis B and C)

DNA Replication

Semi-Conservative Replication

DNA replication is semi-conservative: each new DNA molecule consists of one original strand and one newly synthesised strand.

Process

  1. Helicase unwinds and separates the double helix by breaking hydrogen bonds between complementary bases
  2. DNA polymerase adds complementary nucleotides to each template strand, following the base pairing rules (A-T, C-G)
  3. Leading strand: Synthesised continuously in the 5-prime to 3-prime direction
  4. Lagging strand: Synthesised in short fragments (Okazaki fragments) that are later joined by DNA ligase
  5. Each new DNA molecule contains one original strand and one new strand

Accuracy

DNA polymerase has a proofreading function. If an incorrect nucleotide is added, it is removed and replaced. This gives an error rate of approximately 1 in 10910^9 base pairs.


Protein Synthesis

Transcription

Transcription is the process of copying the genetic information from DNA to messenger RNA (mRNA).

  1. RNA polymerase binds to the promoter region on the DNA template strand
  2. The DNA double helix unwinds locally
  3. RNA polymerase synthesises a complementary mRNA strand using the DNA template (A pairs with U, T pairs with A, C pairs with G, G pairs with C)
  4. The mRNA molecule is released when RNA polymerase reaches the terminator region
  5. In eukaryotes, the pre-mRNA is processed:
    • A cap is added to the 5-prime end
    • A poly-A tail is added to the 3-prime end
    • Introns (non-coding regions) are removed by splicing
    • Exons (coding regions) are joined together

Translation

Translation is the process of synthesising a polypeptide chain from the mRNA template.

  1. The mRNA binds to a ribosome
  2. The ribosome reads the mRNA in codons (groups of three bases)
  3. Transfer RNA (tRNA) molecules bring specific amino acids to the ribosome
  4. Each tRNA has an anticodon that is complementary to the codon on the mRNA
  5. Peptide bonds form between adjacent amino acids (catalysed by peptidyl transferase in the ribosome)
  6. Translation stops when a stop codon (UAA, UAG, UGA) is reached
  7. The polypeptide chain is released and folds into its functional 3D shape

The Genetic Code

  • The genetic code is degenerate: most amino acids are coded for by more than one codon
  • The genetic code is universal: the same codons code for the same amino acids in nearly all organisms
  • The genetic code is non-overlapping: each base is part of only one codon

Additional Practice Questions

More Exam-Style Problems

Question 4: Describe the role of the Golgi apparatus in protein processing and transport.

The Golgi apparatus receives proteins from the rough ER in transport vesicles. It modifies these proteins by adding carbohydrate groups (glycosylation) to form glycoproteins. It sorts proteins and packages them into secretory vesicles for export from the cell (exocytosis), or into lysosomes. The Golgi acts as a processing and distribution centre, ensuring proteins reach their correct destinations.

Question 5: Explain how the structure of the mitochondrion is adapted to its function in aerobic respiration.

The mitochondrion has a double membrane. The inner membrane is folded into cristae, providing a large surface area for the electron transport chain and ATP synthase. The matrix contains enzymes for the Krebs cycle and its own DNA and ribosomes, allowing it to produce some of its own proteins. The small intermembrane space allows the accumulation of protons for the chemiosmotic gradient. These structural features maximise the rate of ATP production.

Question 6: Compare the structure and function of DNA and mRNA.

Structure: DNA is double-stranded with a deoxyribose sugar, thymine as a base, and is very long. mRNA is single-stranded with a ribose sugar, uracil replacing thymine, and is much shorter.

Function: DNA stores genetic information long-term in the nucleus. mRNA carries a copy of the genetic information from the nucleus to the ribosomes for protein synthesis (transient role).

Question 7: Describe the stages of mitosis and explain their significance.

Prophase: Chromosomes condense (become visible), the nuclear envelope breaks down, spindle fibres form, and centrioles move to opposite poles. This prepares the cell for division by organising the genetic material.

Metaphase: Chromosomes align at the metaphase plate (cell equator) with spindle fibres attached to centromeres. This ensures equal distribution of chromosomes to daughter cells.

Anaphase: Sister chromatids separate at the centromeres and are pulled to opposite poles by shortening spindle fibres. This ensures each daughter cell receives identical genetic material.

Telophase: Chromosomes decondense, nuclear envelopes reform, nucleoli reappear, and spindle fibres break down. This reverses the changes of prophase and re-establishes the interphase state.

Cytokinesis: The cytoplasm divides, producing two separate daughter cells.

Question 8: A cell has 20 chromosomes in G1. How many chromosomes and DNA molecules are present at the end of S phase, during metaphase of mitosis, and after cytokinesis?

End of S phase: 20 chromosomes, 40 DNA molecules (each chromosome has been replicated into two sister chromatids).

Metaphase of mitosis: 20 chromosomes (each with 2 chromatids), 40 DNA molecules.

After cytokinesis: 20 chromosomes, 20 DNA molecules (each daughter cell receives 20 single-chromatid chromosomes).


Homeostasis and Cell Communication

Cell Signalling

Cells communicate through chemical messengers called ligands that bind to specific receptors.

Types of cell signalling:

TypeDescriptionDistanceExample
AutocrineCell signals to itselfSame cellGrowth factors
ParacrineCell signals to nearby cellsShort distanceNeurotransmitters
EndocrineHormone travels in bloodLong distanceInsulin, adrenaline
SynapticSignal across a synapseVery shortAcetylcholine
Contact-dependentDirect cell-to-cell contactAdjacent cellsImmune recognition

Receptors

Cell-surface receptors: For large or hydrophilic signalling molecules that cannot cross the cell membrane (e.g., insulin, adrenaline).

Intracellular receptors: For small or hydrophobic signalling molecules that can diffuse through the membrane (e.g., steroid hormones like testosterone, oestrogen).

Signal Transduction

When a ligand binds to a cell-surface receptor, it triggers a cascade of intracellular events:

  1. Signal reception: The ligand binds to the receptor
  2. Signal transduction: The signal is relayed inside the cell, often involving:
    • G-proteins: Activate or inhibit enzymes
    • Second messengers: Small molecules that amplify the signal (e.g., cAMP, Ca2+\mathrm{Ca}^{2+})
    • Enzyme cascades: Kinase cascades that phosphorylate target proteins
  3. Cellular response: The cell changes its activity (e.g., gene expression, metabolism, secretion)
info

Second messengers greatly amplify the signal. One receptor activation can produce many second messenger molecules, each of which can activate many enzyme molecules, creating a large response from a small stimulus.


Immune System

Non-Specific (Innate) Immunity

First line of defence:

  • Skin: physical barrier
  • Mucous membranes: trap pathogens
  • Stomach acid: destroys pathogens
  • Tears, saliva: contain lysozyme (an enzyme that breaks down bacterial cell walls)

Second line of defence:

  • Phagocytes (neutrophils, macrophages): engulf and digest pathogens by phagocytosis
  • Inflammation: increased blood flow, swelling, heat, pain; brings phagocytes to the infection site
  • Fever: raises body temperature, inhibiting pathogen growth and enhancing immune function
  • Interferons: proteins produced by virus-infected cells that inhibit viral replication in neighbouring cells

Specific (Adaptive) Immunity

Cell-mediated response (T cells):

  • T helper cells: release cytokines that stimulate B cells and cytotoxic T cells
  • Cytotoxic T cells (killer T cells): destroy virus-infected cells and cancer cells by inducing apoptosis
  • Memory T cells: provide long-term immunity

Humoral response (B cells):

  • B cells produce antibodies (immunoglobulins) specific to the antigen
  • Plasma cells: short-lived cells that secrete large quantities of antibodies
  • Memory B cells: provide long-term immunity; respond faster and more strongly upon re-exposure

Antibody Structure

An antibody (immunoglobulin) is a Y-shaped protein with:

  • Two identical heavy chains
  • Two identical light chains
  • Variable regions: specific to the antigen (at the tips of the Y)
  • Constant regions: the same for all antibodies of the same class

Types of Antibodies

TypeLocationFunction
IgGBlood, tissue fluidMost abundant; crosses placenta
IgASaliva, tears, breast milk, mucusProtects mucous membranes
IgMBloodFirst antibody produced in primary response
IgEBound to mast cellsAllergic reactions; parasitic infections
IgDB cell surfaceB cell activation

Primary vs Secondary Immune Response

FeaturePrimary ResponseSecondary Response
SpeedSlow (5-10 days)Fast (1-3 days)
Antibody levelLowerHigher
Antibody classMainly IgMMainly IgG
DurationShortLong
Memory cellsProducedAlready present

Worked Example 3 (Immune)

Explain how vaccination provides immunity against a disease.

A vaccine contains a weakened or dead form of the pathogen (or parts of it like antigens). When introduced into the body, it triggers a primary immune response without causing the disease. B cells produce antibodies and memory B cells are formed. If the person is later exposed to the actual pathogen, the memory B cells quickly produce large quantities of antibodies in a secondary response, destroying the pathogen before symptoms develop. This provides active artificial immunity.


Additional Topics

Stem Cells

Definition: Undifferentiated cells that can divide and differentiate into specialised cell types.

TypeSourcePotential
TotipotentEarly embryo (up to 8-cell stage)Can become any cell type + placenta
PluripotentBlastocyst (inner cell mass)Can become any cell type
MultipotentAdult tissues (e.g., bone marrow)Can become limited range of cell types
UnipotentSpecific tissuesCan become only one cell type

Therapeutic uses:

  • Treatment of leukaemia (bone marrow transplants)
  • Potential for regenerative medicine (repairing damaged tissues)
  • Research into disease mechanisms

Ethical considerations:

  • Embryonic stem cells involve destruction of embryos
  • Adult stem cells have more limited potential
  • Induced pluripotent stem cells (iPSCs) offer an alternative

Water Potential and Osmosis Calculations

The water potential of a solution is:

Ψ=Ψs+Ψp\Psi = \Psi_s + \Psi_p

Where:

  • Ψs\Psi_s = solute potential (always negative or zero)
  • Ψp\Psi_p = pressure potential (positive in turgid plant cells, zero in animal cells)

For a solution with no pressure applied:

Ψ=Ψs=iCRT\Psi = \Psi_s = -iCRT

Where:

  • ii = ionisation constant (number of particles per molecule)
  • CC = molar concentration
  • RR = gas constant (8.314Jmol1K18.314 \mathrm{ J mol}^{-1} \mathrm{ K}^{-1})
  • TT = temperature in Kelvin

Worked Example 4 (Water Potential)

Calculate the water potential of a 0.3mol/dm30.3 \mathrm{ mol/dm}^3 sucrose solution at 25C25^\circ\mathrm{C}. (i=1i = 1 for sucrose)

Ψs=iCRT=(1)(0.3)(8.314)(298)=743.3kPa\Psi_s = -iCRT = -(1)(0.3)(8.314)(298) = -743.3 \mathrm{ kPa}

Since there is no pressure: Ψ=743.3kPa\Psi = -743.3 \mathrm{ kPa}

Worked Example 5 (Water Potential)

Calculate the water potential of a 0.2mol/dm30.2 \mathrm{ mol/dm}^3 NaCl\mathrm{NaCl} solution at 20C20^\circ\mathrm{C}. (i=2i = 2 for NaCl\mathrm{NaCl})

Ψs=(2)(0.2)(8.314)(293)=974.4kPa\Psi_s = -(2)(0.2)(8.314)(293) = -974.4 \mathrm{ kPa}

Ψ=974.0kPa\Psi = -974.0 \mathrm{ kPa}


Problem Set

Problem 1: Describe three structural differences between prokaryotic and eukaryotic cells, and explain how each difference relates to the cell's function.

If you get this wrong, revise: Cell Structure -- Prokaryotic vs Eukaryotic Cells

Solution
  1. Nucleus: Eukaryotic cells have a true nucleus with a nuclear envelope, while prokaryotic cells have a nucleoid region (no membrane). The nuclear envelope in eukaryotes separates transcription from translation, allowing mRNA processing (splicing, capping, poly-A tail), enabling more complex gene regulation.

  2. Mitochondria: Eukaryotic cells have mitochondria for aerobic respiration (high ATP yield via oxidative phosphorylation), while prokaryotic cells carry out respiration on their cell membrane (less efficient, limited surface area). Mitochondria provide a large internal surface area (cristae) for the electron transport chain.

  3. Ribosomes: Eukaryotic cells have 80S ribosomes (larger), while prokaryotic cells have 70S ribosomes (smaller). This difference is the basis of antibiotic specificity -- drugs like tetracycline target 70S ribosomes in bacteria without affecting eukaryotic 80S ribosomes.

Problem 2: A red blood cell is placed in a 0.5 mol/dm3^3 sucrose solution. Predict what will happen to the cell and explain your reasoning. (The water potential of the red blood cell cytoplasm is approximately -700 kPa.)

If you get this wrong, revise: Membrane Transport -- Osmosis; Water Potential and Osmosis Calculations

Solution

The water potential of the 0.5 mol/dm3^3 sucrose solution is:

Ψs=iCRT=(1)(0.5)(8.314)(298)=1238.8kPa\Psi_s = -iCRT = -(1)(0.5)(8.314)(298) = -1238.8 \mathrm{ kPa}

Since the solution has a more negative water potential (-1238.8 kPa) than the cell cytoplasm (-700 kPa), water will move out of the cell by osmosis (from higher to lower water potential). The red blood cell will lose water, shrink, and become crenated (wrinkled appearance).

Problem 3: Explain the effect of increasing temperature on enzyme activity from 0 degrees C to 60 degrees C. Refer to kinetic energy, collision frequency, and enzyme structure in your answer.

If you get this wrong, revise: Enzymes -- Factors Affecting Enzyme Activity

Solution

From 0 degrees C to the optimum (~37-40 degrees C): increasing temperature increases the kinetic energy of both enzyme and substrate molecules, leading to more frequent effective collisions between them. The rate of reaction increases as more enzyme-substrate complexes form per unit time.

Beyond the optimum temperature, the increased kinetic energy breaks the hydrogen bonds, ionic bonds, and other weak interactions maintaining the tertiary structure of the enzyme. The active site changes shape (denaturation), and the substrate can no longer bind. Since denaturation is irreversible, the reaction rate decreases sharply and the enzyme is permanently inactivated.

Problem 4: A cell in the G1 phase of the cell cycle has 46 chromosomes. How many chromosomes and DNA molecules are present at the end of S phase, during metaphase of mitosis, and after cytokinesis?

If you get this wrong, revise: Cell Division -- Mitosis; The Cell Cycle

Solution

End of S phase: 46 chromosomes, 92 DNA molecules (each chromosome has been replicated into two sister chromatids, but chromosome count remains 46 because sister chromatids are still joined at the centromere).

Metaphase of mitosis: 46 chromosomes (each with 2 chromatids), 92 DNA molecules. The chromosomes are aligned at the metaphase plate with spindle fibres attached to centromeres.

After cytokinesis: 46 chromosomes, 46 DNA molecules. Each daughter cell receives 46 single-chromatid chromosomes (the chromatids separated during anaphase). The chromosome number is the same as the original cell, maintaining genetic continuity.

Problem 5: Compare the structure and function of DNA and mRNA.

If you get this wrong, revise: DNA Replication; Protein Synthesis

Solution

Structure: DNA is double-stranded (double helix) with a deoxyribose sugar and thymine as a base. mRNA is single-stranded with a ribose sugar and uracil replacing thymine. DNA is very long (entire genome), while mRNA is a shorter copy of a single gene.

Function: DNA stores genetic information long-term in the nucleus. mRNA carries a transient copy of the genetic information from the nucleus to the ribosomes in the cytoplasm for protein synthesis (translation). DNA is self-replicating; mRNA is not.

Stability: DNA is chemically stable (deoxyribose is less reactive than ribose; double-stranded structure provides protection). mRNA is short-lived (ribose is more reactive; single-stranded structure is vulnerable to nucleases), allowing rapid changes in gene expression.

Problem 6: Describe the stages of mitosis and explain their significance in ensuring genetic continuity.

If you get this wrong, revise: Cell Division -- Stages of Mitosis

Solution

Prophase: Chromatin condenses into visible chromosomes (each consisting of two sister chromatids joined at the centromere). The nuclear envelope breaks down, spindle fibres form, and centrioles move to opposite poles. Significance: organises and packages the genetic material for even distribution.

Metaphase: Chromosomes align at the metaphase plate (cell equator) with spindle fibres attached to centromeres. Significance: ensures each daughter cell receives one copy of each chromosome.

Anaphase: Sister chromatids separate at the centromeres and are pulled to opposite poles by shortening spindle fibres. Significance: the critical step that distributes identical genetic material to each daughter cell.

Telophase: Chromosomes decondense, nuclear envelopes reform, nucleoli reappear, and spindle fibres break down. Significance: re-establishes the interphase state in each daughter cell.

Cytokinesis: The cytoplasm divides, producing two separate daughter cells, each genetically identical to the parent cell.

Problem 7: Explain how vaccination provides immunity against a disease, referring to both the primary and secondary immune responses.

If you get this wrong, revise: Immune System -- Specific (Adaptive) Immunity; Primary vs Secondary Immune Response

Solution

A vaccine contains a weakened or dead form of the pathogen (or specific antigens). When introduced into the body, it triggers a primary immune response: B cells are activated by the antigen, divide by mitosis, and differentiate into plasma cells (which secrete antibodies) and memory B cells. T helper cells are also activated and support the B cell response.

If the person is later exposed to the actual pathogen, memory B cells recognise the antigen and rapidly divide, producing large quantities of antibodies in a secondary response. The secondary response is faster (1-3 days vs 5-10 days), produces more antibodies (mainly IgG), and lasts longer. The pathogen is destroyed before it can cause symptoms, providing active artificial immunity.

Problem 8: Describe the role of the Golgi apparatus in protein processing and transport.

If you get this wrong, revise: Cell Organelles -- Golgi Apparatus

Solution

The Golgi apparatus receives proteins from the rough ER in transport vesicles. It modifies these proteins by adding carbohydrate groups (glycosylation) to form glycoproteins. It sorts proteins based on their destination and packages them into secretory vesicles. Different vesicles are targeted to different locations: some fuse with the cell membrane for export (exocytosis), some become lysosomes (in animal cells), and others are transported to other organelles. The Golgi acts as a processing and distribution centre, ensuring proteins reach their correct destinations.

Problem 9: Calculate the water potential of a 0.15 mol/dm3^3 NaCl solution at 25 degrees C. (i=2i = 2 for NaCl.) Determine whether a plant cell with Ψ=800kPa\Psi = -800 \mathrm{ kPa} and Ψp=200kPa\Psi_p = 200 \mathrm{ kPa} would gain or lose water in this solution.

If you get this wrong, revise: Water Potential and Osmosis Calculations

Solution

Ψs=iCRT=(2)(0.15)(8.314)(298)=742.5kPa\Psi_s = -iCRT = -(2)(0.15)(8.314)(298) = -742.5 \mathrm{ kPa}

Since there is no pressure applied to the external solution: Ψsolution=742.5kPa\Psi_{\mathrm{solution}} = -742.5 \mathrm{ kPa}

For the plant cell:

Ψcell=Ψs+Ψp=800+200=600kPa\Psi_{\mathrm{cell}} = \Psi_s + \Psi_p = -800 + 200 = -600 \mathrm{ kPa}

Since Ψsolution\Psi_{\mathrm{solution}} (-742.5 kPa) is more negative than Ψcell\Psi_{\mathrm{cell}} (-600 kPa), water moves from the cell (higher water potential) into the solution (lower water potential). The plant cell would lose water.

Problem 10: Explain how the structure of the mitochondrion is adapted to its function in aerobic respiration.

If you get this wrong, revise: Cell Organelles -- Mitochondria; Cellular Respiration

Solution

The mitochondrion has a double membrane. The inner membrane is folded into cristae, providing a large surface area for the electron transport chain and ATP synthase. The intermembrane space between the two membranes allows protons to accumulate, creating the electrochemical gradient needed for chemiosmosis. The matrix contains enzymes for the Krebs cycle, mitochondrial DNA (allowing the mitochondrion to produce some of its own proteins), and ribosomes. The small volume of the matrix ensures high concentrations of substrates and enzymes, maximising the rate of the Krebs cycle. These features collectively maximise the rate of ATP production through oxidative phosphorylation.


Cellular Respiration in Detail

Glycolysis (Detailed)

Glycolysis occurs in the cytoplasm and does not require oxygen. It is the first stage of both aerobic and anaerobic respiration.

Stages of glycolysis:

StageKey StepsEnergy Change
PhosphorylationGlucose (6C) is phosphorylated twice using 2 ATP, forming hexose biphosphate (6C). This "traps" glucose inside the cell and raises its energy levelConsumes 2 ATP (investment phase)
SplittingHexose biphosphate is split into two molecules of triose phosphate (3C each)No ATP change
OxidationEach triose phosphate is oxidised (dehydrogenated) by NAD+^+, producing 2 NADH (one per triose phosphate)Produces 2 NADH
ATP productionEach triose phosphate is converted to pyruvate (3C), producing 2 ATP per triose phosphate (substrate-level phosphorylation)Produces 4 ATP (2 per triose phosphate)
Net yield2 ATP + 2 NADH per glucose

Glucose (6C)+2NAD++2ADP+2Pi2 Pyruvate (3C)+2NADH+2H++2ATP+2H2O\text{Glucose (6C)} + 2\mathrm{NAD}^+ + 2\mathrm{ADP} + 2\mathrm{P}_i \to 2\text{ Pyruvate (3C)} + 2\mathrm{NADH} + 2\mathrm{H}^+ + 2\mathrm{ATP} + 2\mathrm{H}_2\mathrm{O}

Link reaction (pyruvate oxidation):

  • Occurs in the mitochondrial matrix
  • Each pyruvate (3C) is decarboxylated (loses CO2\mathrm{CO}_2) and dehydrogenated (NAD+^+ reduced to NADH)
  • The remaining 2-carbon acetyl group combines with coenzyme A to form acetyl CoA
  • Per glucose: 2 pyruvate \to 2 acetyl CoA + 2 CO2\mathrm{CO}_2 + 2 NADH

Krebs cycle (citric acid cycle):

  • Occurs in the mitochondrial matrix
  • Each acetyl CoA (2C) combines with oxaloacetate (4C) to form citrate (6C)
  • Through a series of reactions, citrate is converted back to oxaloacetate, releasing:
    • 2 CO2\mathrm{CO}_2 (decarboxylation)
    • 3 NADH (dehydrogenation)
    • 1 FADH2_2 (dehydrogenation)
    • 1 ATP (substrate-level phosphorylation via GTP)
  • Per glucose: 2 turns of the cycle produce 4 CO2\mathrm{CO}_2, 6 NADH, 2 FADH2_2, 2 ATP

Oxidative Phosphorylation

  • Occurs on the inner mitochondrial membrane (cristae)
  • NADH and FADH2_2 donate electrons to the electron transport chain
  • Electrons pass through a series of carriers (complexes I-IV), releasing energy used to pump H+\mathrm{H}^+ into the intermembrane space
  • H+\mathrm{H}^+ flows back through ATP synthase (chemiosmosis), producing ATP
  • Oxygen is the final electron acceptor, combining with H+\mathrm{H}^+ and electrons to form water

Total ATP Yield (Per Glucose)

StageATP (or equivalent)
Glycolysis (net)2 ATP + 2 NADH
Link reaction2 NADH
Krebs cycle2 ATP + 6 NADH + 2 FADH2_2
Oxidative phosphorylationEach NADH produces approximately 2.5 ATP; each FADH2_2 produces approximately 1.5 ATP
Total (approximate)30-32 ATP
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The exact ATP yield varies because the shuttle mechanism that transfers electrons from cytoplasmic NADH into the mitochondria can cost 1 ATP per NADH. The theoretical maximum is 38 ATP, but in practice, the yield is closer to 30-32 ATP due to proton leakage across the inner mitochondrial membrane and the cost of transporting molecules.

Anaerobic Respiration

When oxygen is unavailable, pyruvate cannot enter the mitochondria for oxidative phosphorylation. Cells must regenerate NAD+^+ by alternative pathways to keep glycolysis running.

In animal cells (lactic acid fermentation):

Pyruvate+NADHLDHLactate+NAD+\text{Pyruvate} + \mathrm{NADH} \xrightarrow{\text{LDH}} \text{Lactate} + \mathrm{NAD}^+

  • Net yield: 2 ATP per glucose (only from glycolysis)
  • Lactate accumulates in muscles, causing fatigue and cramping
  • Lactate is transported to the liver and converted back to pyruvate (Cori cycle), which can be oxidised in the Krebs cycle or converted back to glucose

In yeast and plant cells (alcoholic fermentation):

PyruvatedecarboxylaseEthanal+CO2\text{Pyruvate} \xrightarrow{\text{decarboxylase}} \text{Ethanal} + \mathrm{CO}_2

Ethanal+NADHalcohol dehydrogenaseEthanol+NAD+\text{Ethanal} + \mathrm{NADH} \xrightarrow{\text{alcohol dehydrogenase}} \text{Ethanol} + \mathrm{NAD}^+

  • Net yield: 2 ATP per glucose
  • CO2\mathrm{CO}_2 and ethanol are produced as waste products
  • This process is used in brewing (beer) and baking (bread rises due to CO2\mathrm{CO}_2 production)

Cancer Biology

What is Cancer?

Cancer is a group of diseases characterised by uncontrolled cell division, leading to the formation of malignant tumours that can invade surrounding tissues and spread to other parts of the body (metastasis).

Causes of Cancer

Cancer is caused by mutations in genes that regulate the cell cycle. These mutations can be caused by:

FactorDescription
Chemical carcinogensChemicals that damage DNA (e.g., tar in cigarette smoke, benzene, asbestos, aflatoxin in mouldy peanuts)
RadiationIonising radiation (X-rays, gamma rays, UV light) causes DNA damage
Viral infectionSome viruses integrate their DNA into the host genome, disrupting tumour suppressor genes or activating oncogenes
Hereditary factorsInherited mutations in tumour suppressor genes (e.g., BRCA1/BRCA2 mutations increase breast cancer risk)
Chronic inflammationInflammatory cells produce reactive oxygen species that can damage DNA
Gene TypeNormal FunctionEffect When Mutated
Proto-oncogenesPromote controlled cell division (accelerate cell cycle)Become oncogenes when mutated; cause excessive cell division
Tumour suppressor genesInhibit cell division; promote DNA repair; trigger apoptosisLose function when mutated; cell division is no longer restrained
ExamplesProto-oncogene: ras (signals for cell division)p53 (tumour suppressor; halts cell cycle for DNA repair or triggers apoptosis)

Tumour Suppressor p53

The p53 protein is often called the "guardian of the genome." It plays a critical role in preventing cancer:

  1. If DNA damage is detected, p53 halts the cell cycle (at G1 checkpoint) to allow time for DNA repair
  2. If the damage is repairable, p53 activates DNA repair enzymes
  3. If the damage is too severe to repair, p53 triggers apoptosis (programmed cell death), preventing the damaged cell from dividing and potentially becoming cancerous
  4. Approximately 50% of all human cancers involve mutations in the p53 gene

Benign vs Malignant Tumours

FeatureBenign TumourMalignant Tumour
Growth rateSlowRapid
EncapsulationEncapsulated (contained within a fibrous capsule)Not encapsulated; invades surrounding tissue
MetastasisDoes NOT spread to other parts of the bodyCAN spread (metastasise) via blood or lymph
Cell differentiationWell-differentiated (cells look normal)Poorly differentiated (cells look abnormal)
Health impactUsually harmless unless pressing on organsLife-threatening if untreated
RecurrenceRarely recurs after removalMay recur after removal

Worked Example: Carcinogens and DNA Damage

A person smokes 20 cigarettes per day for 30 years. Explain how the chemicals in cigarette smoke can lead to lung cancer, referring to the role of proto-oncogenes and tumour suppressor genes.

Solution

Cigarette smoke contains over 60 known carcinogens, including benzopyrene (a polycyclic aromatic hydrocarbon) and nitrosamines. These chemicals enter the lungs during inhalation and are absorbed into lung epithelial cells.

  1. DNA damage: Carcinogens are metabolised into reactive intermediates that bind to DNA, forming DNA adducts. These adducts cause mutations during DNA replication. Benzopyrene, for example, causes a specific G to T transversion mutation in the p53 gene.

  2. Proto-oncogene activation: Mutations can convert proto-oncogenes (e.g., ras) into oncogenes, causing them to be permanently activated. The ras oncogene produces a protein that continuously signals cells to divide, even in the absence of growth factor signals.

  3. Tumour suppressor gene inactivation: Mutations can inactivate tumour suppressor genes (e.g., p53). Without functional p53, cells with damaged DNA are not arrested for repair and do not undergo apoptosis. Mutations accumulate, and damaged cells continue to divide uncontrollably.

  4. Multiple mutations required: A single mutation is usually insufficient to cause cancer. Cancer typically requires mutations in multiple genes (approximately 5-10 driver mutations). The long duration of exposure (30 years) allows multiple mutations to accumulate in the same cell lineage.

  5. Tumour formation: Once enough mutations accumulate, a cell begins dividing uncontrollably, forming a malignant tumour that can invade surrounding lung tissue and metastasise to other organs via the bloodstream or lymphatic system.


Additional Problem Set

Problem 11: Compare aerobic and anaerobic respiration in terms of location, substrates, products, and ATP yield. Explain why anaerobic respiration produces much less ATP per glucose molecule.

If you get this wrong, revise: Cellular Respiration in Detail

Solution
FeatureAerobic RespirationAnaerobic Respiration (animals)
LocationCytoplasm (glycolysis) + mitochondria (link reaction, Krebs cycle, oxidative phosphorylation)Cytoplasm only (glycolysis only)
OxygenRequired (final electron acceptor)Not required
SubstratesGlucoseGlucose
ProductsCO2\mathrm{CO}_2, H2O\mathrm{H}_2\mathrm{O}, ATP (30-32)Lactate, ATP (2)
ATP yieldApproximately 30-32 ATP per glucose2 ATP per glucose
NAD+^+ regenerationVia oxidative phosphorylation (electron transport chain)Via conversion of pyruvate to lactate (NADH oxidised to NAD+^+)

Anaerobic respiration produces much less ATP because only glycolysis occurs, yielding a net 2 ATP. The much larger ATP yield of aerobic respiration comes from oxidative phosphorylation, which requires the electron transport chain in the inner mitochondrial membrane. NADH and FADH2_2 from glycolysis, the link reaction, and the Krebs cycle donate electrons to the electron transport chain, and the energy released pumps protons across the membrane. The resulting proton gradient drives ATP synthase, producing approximately 28-30 ATP. Without oxygen as the final electron acceptor, the electron transport chain cannot operate, and this massive ATP yield is lost.

Problem 12: Explain the roles of proto-oncogenes and tumour suppressor genes in regulating the cell cycle. Explain how mutations in both types of gene can contribute to cancer development.

If you get this wrong, revise: Cancer Biology

Solution

Proto-oncogenes promote cell division when activated by growth factor signals. They encode proteins involved in cell cycle progression (e.g., ras encodes a GTPase that transmits growth signals; myc encodes a transcription factor that activates genes for cell division). When mutated, proto-oncogenes become oncogenes that are permanently activated, causing cells to divide continuously even without external growth signals. This is analogous to a car with a stuck accelerator.

Tumour suppressor genes inhibit cell division, promote DNA repair, or trigger apoptosis when DNA is damaged. For example, p53 halts the cell cycle at the G1 checkpoint if DNA damage is detected, allowing time for repair; if damage is irreparable, p53 triggers apoptosis. When mutated, tumour suppressor genes lose their function, so damaged cells continue dividing without repair or death. This is analogous to a car with no brakes.

Cancer typically requires mutations in BOTH types of gene: an oncogene drives excessive cell division (accelerator stuck), while loss of tumour suppressor function removes the brakes that would normally halt or eliminate damaged cells. This combination allows cells to divide uncontrollably and accumulate further mutations, leading to malignant tumour formation.



Membrane Transport in Detail

Facilitated Diffusion

Facilitated diffusion is the passive movement of molecules across a membrane via transmembrane proteins. Like simple diffusion, it moves molecules down their concentration gradient and does not require energy. Unlike simple diffusion, it requires specific carrier proteins or channel proteins.

FeatureSimple DiffusionFacilitated Diffusion
Requires proteinsNoYes (channel proteins or carrier proteins)
SelectiveNo (any small, non-polar molecule)Yes (specific to particular molecules)
SaturationNo (rate increases with concentration indefinitely)Yes (rate plateaus when all proteins are occupied)
Energy requiredNoNo
DirectionDown concentration gradientDown concentration gradient
Molecules transportedO2\mathrm{O}_2, CO2\mathrm{CO}_2, small lipids, waterGlucose (via GLUT transporters), amino acids, ions (Na+\mathrm{Na}^+, K+\mathrm{K}^+)

Channel proteins:

  • Form water-filled pores through the membrane
  • Allow specific ions or molecules to pass through by diffusion
  • Types:
    • Ion channels: Allow specific ions to pass (e.g., Na+\mathrm{Na}^+ channels, K+\mathrm{K}^+ channels, Ca2+\mathrm{Ca}^{2+} channels)
    • Aquaporins: Channel proteins specific to water molecules; allow rapid osmosis (approximately 10 times faster than diffusion through the lipid bilayer)
  • Gated channels: Open or close in response to specific stimuli:
    • Voltage-gated channels: Open in response to changes in membrane potential (essential for nerve impulse transmission)
    • Ligand-gated channels: Open when a specific chemical (ligand) binds (e.g., neurotransmitter-gated channels at synapses)
    • Mechanically-gated channels: Open in response to physical deformation (e.g., in hair cells of the cochlea)

Carrier proteins:

  • Bind to specific molecules and undergo a conformational change to transport them across the membrane
  • Can transport larger molecules (e.g., glucose, amino acids) that cannot pass through channels
  • Exhibit saturation kinetics: when all carrier proteins are occupied, the transport rate plateaus regardless of further increases in concentration
  • Example: GLUT1 transporter for glucose in red blood cells

Active Transport

Active transport moves molecules against their concentration gradient (from low to high concentration), requiring energy in the form of ATP.

FeaturePrimary Active TransportSecondary Active Transport (Co-transport)
Energy sourceATP hydrolysis directlyUses an ion gradient established by primary active transport
Direct ATP useYesNo (indirect)
ExampleNa+/K+\mathrm{Na}^+/\mathrm{K}^+ pump; H+\mathrm{H}^+ ATPase in stomachNa+\mathrm{Na}^+-glucose co-transport in small intestine; Na+\mathrm{Na}^+-amino acid co-transport
DirectionCan move substances in either directionMoves both the driving ion and the transported substance in the same (symport) or opposite (antiport) direction

The sodium-potassium pump (detailed mechanism):

  1. Three Na+\mathrm{Na}^+ ions bind to the intracellular side of the pump protein
  2. ATP binds and is hydrolysed to ADP and Pi\mathrm{P}_i
  3. The phosphate group is transferred to the pump protein (phosphorylation), changing its conformation
  4. The conformational change exposes the Na+\mathrm{Na}^+ binding sites to the extracellular side; Na+\mathrm{Na}^+ is released
  5. Two K+\mathrm{K}^+ ions from the extracellular side bind to the pump
  6. The phosphate group is released (dephosphorylation), returning the pump to its original conformation
  7. The conformational change exposes the K+\mathrm{K}^+ binding sites to the intracellular side; K+\mathrm{K}^+ is released

Significance of the sodium-potassium pump:

  • Maintains the resting potential of neurons (by creating concentration gradients for Na+\mathrm{Na}^+ and K+\mathrm{K}^+)
  • Maintains cell volume (by controlling osmotic balance)
  • Provides the Na+\mathrm{Na}^+ gradient that drives secondary active transport (e.g., Na+\mathrm{Na}^+-glucose co-transport in the small intestine and kidney)
  • Essential for nerve impulse transmission and muscle contraction

Bulk Transport: Endocytosis and Exocytosis

Large molecules (proteins, polysaccharides) and particles are transported across the membrane in membrane-bound vesicles.

ProcessDescriptionEnergy RequiredExample
EndocytosisCell membrane engulfs material, forming a vesicle inside the cellYes (ATP)White blood cells engulfing bacteria (phagocytosis)
ExocytosisVesicles inside the cell fuse with the cell membrane, releasing their contents outsideYes (ATP)Release of neurotransmitters at synapses; secretion of mucus and enzymes
Phagocytosis"Cell eating": large solid particles are engulfed by extensions of the membrane (pseudopodia)Yes (ATP)Phagocytes engulfing bacteria
Pinocytosis"Cell drinking": small droplets of extracellular fluid are taken into the cell in small vesiclesYes (ATP)Uptake of dissolved nutrients by microorganisms

Protein Synthesis in Detail

Transcription

Transcription is the process of copying the genetic code from DNA into mRNA.

Steps:

  1. Initiation: RNA polymerase binds to the promoter region of the gene (upstream of the coding sequence). Transcription factors help position the polymerase correctly.
  2. Elongation: RNA polymerase unwinds the DNA double helix and synthesises a complementary mRNA strand in the 5' to 3' direction, using the template (antisense) strand of DNA. RNA polymerase adds RNA nucleotides complementary to the DNA template: A pairs with U (not T in RNA), G pairs with C.
  3. Termination: RNA polymerase reaches a terminator sequence and detaches from the DNA. The pre-mRNA is released.

Post-transcriptional modifications (in eukaryotes only):

  1. 5' capping: A modified guanine nucleotide (7-methylguanosine) is added to the 5' end. This protects the mRNA from degradation and helps ribosomes recognise it for translation.
  2. 3' polyadenylation: A poly-A tail (150-200 adenine nucleotides) is added to the 3' end. This aids in mRNA stability and export from the nucleus.
  3. Splicing: Introns (non-coding regions) are removed, and exons (coding regions) are joined together by the spliceosome. Alternative splicing allows a single gene to produce multiple different mRNA variants (and therefore multiple different proteins).

Translation

Translation is the process of synthesising a polypeptide chain from the mRNA code.

Steps:

  1. Initiation: The small ribosomal subunit binds to the 5' end of the mRNA and moves along until it reaches the start codon (AUG). The initiator tRNA carrying methionine binds to the start codon. The large ribosomal subunit joins, forming the complete ribosome with three sites: A (aminoacyl), P (peptidyl), and E (exit).
  2. Elongation: A tRNA carrying the appropriate amino acid enters the A site, its anticodon base-pairing with the codon on the mRNA. A peptide bond forms between the amino acid in the P site and the new amino acid in the A site (catalysed by peptidyl transferase). The ribosome translocates by one codon: the empty tRNA moves to the E site and exits; the tRNA with the growing polypeptide moves to the P site; the next codon is exposed in the A site.
  3. Termination: When a stop codon (UAA, UAG, or UGA) is reached in the A site, no tRNA can bind. A release factor protein enters the A site, causing the polypeptide to be released and the ribosome to dissociate.

One gene, one polypeptide (generally): Each gene codes for a specific polypeptide chain. The sequence of codons on the mRNA determines the sequence of amino acids in the polypeptide.

tip

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Cell Division in Detail

The Cell Cycle

PhaseDescriptionDuration (typical mammalian cell)
G1 (Gap 1)Cell grows in size; synthesises proteins and organelles; carries out normal metabolic functions; G1 checkpoint checks cell size and DNA integrity~10-12 hours
S (Synthesis)DNA replication occurs; each chromosome is duplicated to form two sister chromatids joined at the centromere~6-8 hours
G2 (Gap 2)Cell continues to grow; synthesises proteins needed for mitosis (e.g., tubulin for spindle fibres); G2 checkpoint checks DNA replication is complete and error-free~3-4 hours
M (Mitosis)Nuclear division; sister chromatids separate and move to opposite poles of the cell~1-2 hours
C (Cytokinesis)Cytoplasm divides; two daughter cells are formedOccurs with or after M phase

Total cell cycle duration: ~24 hours (varies widely: intestinal epithelial cells divide every ~12 hours; nerve cells rarely or never divide after maturity)

Control of the Cell Cycle

The cell cycle is controlled by cyclins and cyclin-dependent kinases (CDKs):

CheckpointLocationWhat is CheckedOutcome if Failed
G1 checkpoint (restriction point)Late G1 phaseCell size adequate? Nutrients available? Growth signals present? DNA undamaged?Cell enters G0 (resting phase) or undergoes apoptosis
G2 checkpointEnd of G2 phaseDNA replication complete and error-free? All proteins needed for mitosis synthesised?Cell cycle arrests; DNA repair attempted; apoptosis if damage is irreparable
M checkpoint (spindle assembly checkpoint)Metaphase of mitosisAre all chromosomes properly attached to spindle fibres at the metaphase plate?Anaphase is delayed; prevents unequal distribution of chromosomes

Cyclin-CDK mechanism:

  • Cyclins are proteins whose concentration rises and falls at specific points in the cell cycle
  • CDKs are enzymes that are always present but inactive on their own
  • When a cyclin binds to a CDK, the cyclin-CDK complex becomes active and phosphorylates target proteins, triggering the next phase of the cell cycle
  • After the phase is complete, the cyclin is degraded and the CDK becomes inactive again
  • Different cyclins control different checkpoints (e.g., cyclin D-CDK4/6 for G1 checkpoint; cyclin B-CDK1 for G2/M transition)

Mitosis vs Meiosis: Detailed Comparison

FeatureMitosisMeiosis
Number of divisions12 (meiosis I and meiosis II)
Number of daughter cells24
Chromosome numberSame as parent (diploid \rightarrow diploid, 2n \rightarrow 2n)Half of parent (diploid \rightarrow haploid, 2n \rightarrow n)
Genetic variationNo (daughter cells are genetically identical to the parent and to each other)Yes (daughter cells are genetically different from the parent and from each other due to crossing over and independent assortment)
Crossing overNoYes (during prophase I)
Homologous pairs separateNo (sister chromatids separate in anaphase)Yes (homologous chromosomes separate in anaphase I)
Sister chromatids separateYes (in anaphase)Yes (in anaphase II, NOT anaphase I)
Occurs inSomatic cells (body cells) for growth, repair, and asexual reproductionGerm cells in the gonads (testes and ovaries) to produce gametes
Metaphase I alignmentIndividual chromosomes line up at the metaphase plateHomologous pairs line up at the metaphase plate (bivalents/tetrads)

Meiosis I vs Meiosis II

FeatureMeiosis IMeiosis II
ProphaseHomologous chromosomes pair up (synapsis) to form bivalents; crossing over occurs between non-sister chromatidsNo pairing of homologous chromosomes; no crossing over
MetaphaseBivalents (homologous pairs) align at the metaphase plate; one chromosome from each pair faces each poleIndividual chromosomes (each consisting of two sister chromatids) align at the metaphase plate
AnaphaseHomologous chromosomes separate and move to opposite poles (sister chromatids remain attached at the centromere)Sister chromatids separate and move to opposite poles
TelophaseTwo daughter cells are formed, each with half the number of chromosomes (each chromosome still consists of two chromatids)Four daughter cells are formed, each with half the number of chromosomes (each chromosome consists of a single chromatid)
Reduction division?Yes (diploid \rightarrow haploid)No (haploid \rightarrow haploid, but each chromosome is now a single chromatid)

The Significance of Meiosis

  1. Produces haploid gametes: Ensures that fertilisation restores the diploid chromosome number (n + n = 2n)
  2. Generates genetic variation through:
    • Crossing over (recombination): During prophase I, non-sister chromatids of homologous chromosomes exchange segments of DNA at chiasmata. This creates new combinations of alleles on the same chromosome
    • Independent assortment: During metaphase I, the orientation of each bivalent on the metaphase plate is random. With 23 pairs of chromosomes in humans, this gives 2232^{23} (\approx 8.4 million) possible combinations of chromosomes in the gametes
  3. Prevents chromosome doubling: Without meiosis, the chromosome number would double with each generation (2n \rightarrow 4n \rightarrow 8n...)

Stem Cells

Types of Stem Cells

TypeSourcePotencyUses / Potential Uses
TotipotentZygote; early embryo (up to 4-cell stage in humans)Can develop into ANY cell type AND extraembryonic tissues (placenta, umbilical cord)Research; not used therapeutically
PluripotentEmbryonic stem cells (from the inner cell mass of the blastocyst, ~5-7 days after fertilisation)Can develop into ANY cell type of the body (over 200 types), but NOT extraembryonic tissuesResearch; potential for regenerative medicine; treatment of degenerative diseases
MultipotentAdult (somatic) stem cells found in specific tissues (bone marrow, skin, brain, liver)Can develop into a limited range of cell types related to their tissue of originBone marrow transplants; skin grafts; treatment of leukaemia
UnipotentCommitted to developing into only ONE cell typeCan only produce one cell typeLimited use; muscle satellite cells

Sources of Stem Cells

SourceTypeAdvantagesDisadvantages / Ethical Issues
Embryos (IVF clinics)Embryonic (pluripotent)Can differentiate into any cell type; unlimited self-renewal in cultureEthical concerns (destruction of embryo); risk of tumour formation if not properly controlled
Umbilical cord bloodAdult (multipotent)Rich in haematopoietic stem cells; less rejection risk (fewer MHC molecules on cord blood cells); non-invasive collectionLimited number of stem cells per cord; only treats blood-related disorders
Bone marrowAdult (multipotent)Well-established technique (bone marrow transplants since 1960s); donor can regenerate marrowPainful extraction; risk of infection; limited cell types
Induced pluripotent stem cells (iPSCs)Pluripotent (reprogrammed)No embryo destruction; patient-specific (no rejection risk); can differentiate into any cell typeRisk of mutations during reprogramming; less efficient than embryonic stem cells
Adipose tissue (fat)Adult (multipotent)Abundant source; easy extraction (liposuction); can differentiate into bone, cartilage, fat, muscle cellsLimited differentiation potential compared to embryonic stem cells

Induced Pluripotent Stem Cells (iPSCs)

  • Discovered by Shinya Yamanaka (Nobel Prize, 2012)
  • Adult somatic cells (e.g., skin fibroblasts) are reprogrammed to a pluripotent state by introducing four transcription factors: Oct4, Sox2, Klf4, and c-Myc (the "Yamanaka factors")
  • iPSCs behave similarly to embryonic stem cells but avoid the ethical issues associated with embryo destruction
  • Potential applications: patient-specific cell therapy (e.g., replacing damaged neurons in Parkinson's disease), drug testing on patient-specific cells, disease modelling

Common Pitfalls

  • Chromosomes and chromatids are different. Before DNA replication: each chromosome consists of ONE chromatid. After DNA replication (S phase): each chromosome consists of TWO sister chromatids joined at the centromere. After anaphase of mitosis (or anaphase II of meiosis): the chromatids separate and are now called chromosomes
  • In meiosis I, homologous chromosomes separate, NOT sister chromatids. Sister chromatids separate in meiosis II (and in mitosis). If you confuse these, you will get the wrong chromosome numbers in the daughter cells
  • The cell cycle has THREE checkpoints (G1, G2, M), not two. Each checkpoint checks for different things
  • Mitosis produces 2 genetically identical diploid daughter cells; meiosis produces 4 genetically different haploid daughter cells. This is the fundamental distinction

Biological Molecules in Detail

Carbohydrates

TypeElementsDescriptionExamplesFunction(s)
MonosaccharidesC, H, OSingle sugar units; general formula (CH2_2O)n_n; sweet-tasting; soluble in waterGlucose (α\alpha and β\beta), fructose, galactose, ribose, deoxyriboseEnergy source; building blocks for larger carbohydrates; ribose/deoxyribose in nucleic acids
DisaccharidesC, H, OTwo monosaccharides joined by a glycosidic bond (condensation reaction); general formula C12_{12}H22_{22}O11_{11}Maltose (glucose + glucose); sucrose (glucose + fructose); lactose (glucose + galactose)Energy source; transport form of sugars
PolysaccharidesC, H, OMany monosaccharides joined by glycosidic bonds; insoluble (except glycogen); large moleculesStarch (plants), glycogen (animals), cellulose (plants), chitin (insects, fungi)Energy storage (starch, glycogen); structural support (cellulose, chitin)

Starch: A mixture of two polysaccharides:

  • Amylose: Unbranched chain of α\alpha-glucose molecules joined by 1,4-glycosidic bonds; forms a helix; 20-30% of starch
  • Amylopectin: Branched chain of α\alpha-glucose molecules with 1,4-glycosidic bonds in the main chain and 1,6-glycosidic bonds at branch points; 70-80% of starch; more readily digested than amylose because the branches provide more ends for enzymes to work on

Cellulose: Long, unbranched chains of β\beta-glucose joined by 1,4-glycosidic bonds. Every alternate β\beta-glucose molecule is rotated 180 degrees, allowing hydrogen bonds to form between adjacent chains. These hydrogen bonds create strong, rigid microfibrils that provide structural support to plant cell walls. Cellulose is NOT digestible by humans because we lack the enzyme cellulase.

Glycogen: Highly branched polymer of α\alpha-glucose (similar to amylopectin but more branched); stored in liver and muscle cells; the many branch points provide many ends for rapid glycogenolysis when glucose is needed.

Lipids

TypeDescriptionExamplesFunction(s)
TriglyceridesGlycerol + 3 fatty acids joined by ester bonds (condensation reaction)Fats (solid at room temp, mostly saturated); oils (liquid at room temp, mostly unsaturated)Energy storage (long-term); insulation; buoyancy; protection
PhospholipidsGlycerol + 2 fatty acids + phosphate group (hydrophilic head, hydrophobic tails)LecithinMain component of cell membranes; forms the phospholipid bilayer
CholesterolSteroid lipid (four fused carbon rings); small, flat moleculeFound in animal cell membranesModulates membrane fluidity; precursor for steroid hormones (testosterone, oestrogen, cortisol) and bile salts
WaxesLong-chain fatty acids bonded to long-chain alcoholsCuticle on plant leaves; beeswax; earwaxWaterproof coating; protection

Proteins

LevelDescriptionType of Bond
Primary structureThe specific sequence of amino acids in the polypeptide chain, determined by the gene (DNA sequence)Peptide bonds (between amino acids)
Secondary structureRegular folding patterns of the polypeptide chain caused by hydrogen bonding between amino groups and carboxyl groups of the peptide backboneHydrogen bonds
Tertiary structureThe overall 3D shape of a single polypeptide chain, stabilised by various interactionsHydrogen bonds; ionic bonds; disulfide bridges; hydrophobic interactions
Quaternary structureThe arrangement of two or more polypeptide chains (subunits) into a functional proteinSame as tertiary (plus interactions between subunits)
Protein TypeDescriptionExamples
Globular proteinsRoughly spherical; soluble in water; function mainly in metabolic roles (enzymes, antibodies, hormones, transport proteins)Haemoglobin; enzymes (amylase, catalase); antibodies; insulin
Fibrous proteinsLong, rod-shaped; insoluble in water; function mainly in structural rolesCollagen (tendons, skin, bones); keratin (hair, nails); elastin (artery walls, skin)

Nucleic Acids

ComponentDNARNA
Full nameDeoxyribonucleic acidRibonucleic acid
SugarDeoxyribose (one fewer oxygen than ribose)Ribose
BasesAdenine (A), Thymine (T), Cytosine (C), Guanine (G)Adenine (A), Uracil (U), Cytosine (C), Guanine (G)
StructureDouble-stranded helix (two antiparallel strands held together by hydrogen bonds between complementary base pairs)Usually single-stranded (though it can fold back on itself to form secondary structures such as hairpin loops)
Base pairingA-T (2 hydrogen bonds); G-C (3 hydrogen bonds)A-U (2 hydrogen bonds); G-C (3 hydrogen bonds)
StrandsAntiparallel (one strand runs 5' \rightarrow 3', the other runs 3' \rightarrow 5')Single strand (5' \rightarrow 3')
LocationNucleus (in eukaryotes); also in mitochondria and chloroplastsNucleus (mRNA is transcribed here); cytoplasm (mRNA is translated here); also in ribosomes (rRNA)
TypesOne type (DNA)mRNA (messenger); tRNA (transfer); rRNA (ribosomal)
FunctionStores genetic information; passes genetic information from one generation to the next; template for RNA synthesismRNA: carries genetic information from DNA to the ribosome for protein synthesis. tRNA: carries amino acids to the ribosome. rRNA: structural and catalytic component of ribosomes

Water

Property of WaterImportance to Living Organisms
SolventWater is an excellent solvent for polar and ionic substances (due to its polarity); many biochemical reactions take place in aqueous solution
High specific heat capacityWater absorbs a lot of heat energy before its temperature changes significantly; this helps organisms maintain a stable internal temperature (homeostasis) and prevents large temperature fluctuations in aquatic environments
High latent heat of vaporisationA lot of energy is required to evaporate water; this makes sweating an effective cooling mechanism for mammals; evaporation of water from tropical forests contributes to cloud formation and rainfall
Cohesion and surface tensionHydrogen bonds between water molecules create strong cohesion; this allows water to be pulled through xylem vessels (transpiration stream); surface tension allows some insects to walk on water
High density (ice floats)Water is less dense as a solid (ice) than as a liquid because hydrogen bonds hold water molecules in an open lattice structure; this insulates the water below, allowing aquatic organisms to survive in winter
TransparencyWater is transparent to visible light; this allows photosynthesis to occur in aquatic environments (light can penetrate to submerged plants and algae)
ReactantWater is a reactant in hydrolysis reactions (e.g., digestion of polymers) and photosynthesis; a product of condensation reactions and aerobic respiration

Enzymes in Detail

Lock-and-Key vs Induced-Fit Model

ModelDescriptionEvidence
Lock and keyThe active site of the enzyme has a rigid, fixed shape that is exactly complementary to the shape of the substrate (like a key fits a lock)Explains enzyme specificity but is an oversimplification
Induced fitThe active site is flexible; when the substrate enters the active site, the enzyme changes shape slightly to fit more closely around the substrate; this puts strain on the substrate, weakening bonds and lowering the activation energySupported by X-ray crystallography studies showing enzyme-substrate complexes; explains why some enzymes can catalyse reactions of slightly different substrates

Factors Affecting Enzyme Activity

FactorEffectGraph ShapeExplanation
TemperatureRate increases up to an optimum, then decreases sharplyBell curveIncreasing temperature increases kinetic energy (more enzyme-substrate collisions); above the optimum, the enzyme denatures (active site changes shape and substrate can no longer bind)
pHRate increases up to an optimum, then decreasesBell curveChanges in pH alter the charges on amino acid residues in the active site, disrupting the ionic and hydrogen bonds that maintain the tertiary structure; extreme pH causes denaturation
Substrate concentrationRate increases proportionally at low concentrations, then plateaus (Vmax)Hyperbolic (rectangular) curveAt low [substrate], increasing [substrate] increases the number of enzyme-substrate collisions; at high [substrate], all active sites are occupied at all times (enzyme saturation); Vmax depends on enzyme concentration
Enzyme concentrationRate increases proportionallyStraight line (through origin)More enzyme molecules = more active sites available = more enzyme-substrate complexes formed per unit time
Inhibitor concentrationDepends on inhibitor type (competitive or non-competitive)VariesSee below

Types of Inhibition

TypeDescriptionEffect on VmaxEffect on Km_mReversibility
CompetitiveInhibitor has a similar shape to the substrate and competes for the active siteVmax unchanged (high [substrate] outcompetes inhibitor)Km_m increased (higher [substrate] needed to reach half Vmax)Reversible (can be overcome by increasing [substrate])
Non-competitiveInhibitor binds to a site other than the active site (allosteric site), causing a conformational change that alters the active siteVmax decreased (inhibitor cannot be overcome)Km_m unchanged (substrate affinity is not affected, but maximum rate is reduced)Usually reversible

Common Pitfalls

  • Starch is NOT digestible by all organisms. Humans can digest starch (amylase breaks the α\alpha-glycosidic bonds) but CANNOT digest cellulose (β\beta-glycosidic bonds). Herbivores (cows, rabbits) can digest cellulose because they have symbiotic bacteria in their gut that produce cellulase
  • Lipids contain more energy per gram than carbohydrates (approximately 39 kJ/g vs 17 kJ/g). This is because lipids have a higher proportion of C-H bonds (which release more energy when oxidised) and very little oxygen (more energy released per gram of carbon oxidised)
  • DNA and RNA differ in three ways: sugar (deoxyribose vs ribose), bases (T vs U), and structure (double-stranded vs single-stranded). Students often forget one of these differences
  • The primary structure of a protein is determined by the DNA sequence (gene). Changes in the DNA sequence (mutations) can alter the primary structure, which can change the tertiary structure, which can change the function of the protein. This is the molecular basis of many genetic diseases (e.g., sickle cell anaemia: a single amino acid change in the beta-globin protein)
  • Non-competitive inhibition reduces Vmax but does NOT change Km_m. Competitive inhibition increases Km_m but does NOT change Vmax. Students frequently confuse these effects**